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3 years ago

One side of a rectangle is 3 times the length of another side. The difference in their lengths is 10 feet

Mathematics

1 answer:

elena55 [62]3 years ago

4 0

Answer:

5 feet & 15 feet

Step-by-step explanation:

The question is to find the lengths of 2 sides of the rectangle.

Solution:

Let shorter side be "x"

Let longer side be "y"

From the question, we can write:

y = 3x

also

y - x = 10

Now, putting the first on second equation, we get:

y - x = 10

3x - x = 10

2x = 10

x = 10/2 = 5

Now, y = 3x, y = 3(5) = 15

So we can say the lengths of 2 sides of the rectangle is 5 feet & 15 feet

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SVETLANKA909090 [29]

Answer: y=7x+1

Step-by-step explanation: Find any equation parallel to the line.

Hope this helps you out! ☺

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3 years ago

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Situation:

Arturiano [62]

Answer:

t = 6162 years

Step-by-step explanation:

Apparently you are asked to use the constant k = 0.0001 instead of the most common 0.00012. We'll answer the problem using such number you typed, but make sure that there is no omission in your typing.

The equation to use is that for carbon decay:

$N(t)=N_0\,e^{-0.0001\,\,t}$

If the skull contains 54% of its original amount of C14, then that means that :

$N(t)=0.54 \,\,N_0$

we use this to solve for the time (t) in our equation:

$0.54\,\,N_0=N_0\,e^{-0.0001\,\,t}\\\frac{0.54\,\,N_0}{N_0}=e^{-0.0001\,\,t}\\0.54=e^{-0.0001\,\,t}\\ln(0.54)=-0.0001\,\,t\\t=\frac{ln(0.54)}{-0.0001} \\t=6161.86\,\,years$

which rounded to the nearest year as requested gives :

t = 6162 years

8 0

2 years ago

P=2W+2L solve for W

WARRIOR [948]

Answer:

What's the value for P and L?

Step-by-step explanation:

2W = 2L - P

W = (2L - P) / 2

5 0

3 years ago

Mr. Jones bought a cloth of length 3890 cm. How much is the length in m and cm?

devlian [24]

Answer:

38m and 90cm

1m = 100cm

3890cm = 38m and 90cm

Step-by-step explanation:

1m = 100cm

3890cm = 38m and 90cm

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2 years ago

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Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

 $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago