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lana66690 [7]
3 years ago
15

Find the area of a triangle with legs that are: 9 mm, 6 mm, and 12 mm.

Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

Step-by-step explanation:

a = 9 mm ;  b = 6 mm  ;  c = 12 mm

S = (a + b +c) / 2

  = \dfrac{9 + 6 + 12}{2}\\\\= \dfrac{27}{2}\\\\= 13.5 \ mm

S - a = 13.5 - 9 = 4.5 mm

s -b = 13.5 - 6 = 7.5 mm

s -c = 13.5 - 12 = 1.5  mm

Area = \sqrt{s(s-a)(s-b)(s-c)}

       = \sqrt{13.5 * 4.5 * 7.5 * 1.5} \\\\=  \sqrt{683.4375} \\\\=26.1 \ mm^{2}

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