The Network Mapper (Nmap) commands that would be useful on this test network are:
- nmap xxx.xxx.x.x -p
- nmap xxx.xxx.x.x -A
<h3>What is a
penetration test?</h3>
A penetration test can be defined as a cybersecurity technique that simulates a cyber attack against an end user's computer system, so as to scan, identify, test and check for exploitable vulnerabilities in the following:
This ultimately implies that, a penetration test avails an tester the ability to exploit a weakness and potential security threats on a test network as a privileged user, during vulnerability assessments of the system.
<h3>The Network Mapper (Nmap) commands.</h3>
In this scenario, the Network Mapper (Nmap) commands that would be useful on this test network are:
- nmap xxx.xxx.x.x -p
- nmap xxx.xxx.x.x -A
Read more on penetration test here: brainly.com/question/25813524
Mobile phones transmit and receive signals using electromagnetic waves, that is, wireless signal are electromagnetic waves which can travel through a vacuum, they do not need a medium or matter.
<h3>What are electromagnetic waves?</h3>
They are generated by electrical and magnetic particles moving at the same time (oscillating).
<h3>Characteristics of electromagnetic waves</h3>
- Network waves are electromagnetic waves.
- A mobile phone has coverage when it receives electromagnetic waves from at least one base station.
- They do not necessarily require a material medium for their propagation.
Therefore, we can conclude that electromagnetic waves are those that do not need a material medium to propagate and include, among others, radio, television and telephone waves.
Learn more about electromagnetic waves here: brainly.com/question/13803241
Answer:
i have no idea what the answer is
Explanation:
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
To accomplish this without using a loop,
we can use math on a string.
Example:
print("apple" * 8)
Output:
appleappleappleappleappleappleappleapple
In this example,
the multiplication by 8 actually creates 8 copies of the string.
So that's the type of logic we want to apply to our problem.
<span>def powersOfTwo(number):
if number >= 0:
return print("*" * 2**number)
else:
<span>return
Hmm I can't make indentations in this box,
so it's doesn't format correctly.
Hopefully you get the idea though.
We're taking the string containing an asterisk and copying it 2^(number) times.
Beyond that you will need to call the function below.
Test it with some different values.
powersOfTwo(4) should print 2^4 asterisks: ****************</span></span>
