Answer:
Blocking Mode
Explanation:
Spanning Tree Protocol is used to allow path redundancy in the network without creating cycles/circles also called loops.
When two parts of the switched network are connected via two or more Layer 2 switches this result in a loop.
This affects the performance of the network as the result of broadcast packets flooding.
STP puts one port of the switch to forwarding mode and the rest of the ports within the same part of the network to the blocking mode to avoid broadcast packet flooding. STP puts all the ports that are allowing redundant paths to blocking mode and the one port that is left after this is placed in forward mode.
Spanning Tree Algorithm is used by STP to determine the optimal path of switch to the network.
Bridge Protocol Data Units are used to share the information about the optimal path determined by the spanning tree algorithm with other switches.
This information helps STP to eliminate the redundant paths.
So this is how STP allows only one active path to the destination while blocking all other paths to avoid switching loop.
Answer:
public static void print_popcorn_time(int bag_ounces){
if(bag_ounces<3){
System.out.println("Too Small");
}
else if(bag_ounces>10){
System.out.println("Too Large");
}
else{
bag_ounces*=6;
System.out.println(bag_ounces+" seconds");
}
}
Explanation:
Using Java prograamming Language.
The Method (function) print_popcorn_time is defined to accept a single parameter of type int
Using if...else if ....else statements it prints the expected output given in the question
A complete java program calling the method is given below
public class num6 {
public static void main(String[] args) {
int bagOunces = 7;
print_popcorn_time(bagOunces);
}
public static void print_popcorn_time(int bag_ounces){
if(bag_ounces<3){
System.out.println("Too Small");
}
else if(bag_ounces>10){
System.out.println("Too Large");
}
else{
bag_ounces*=6;
System.out.println(bag_ounces+" seconds");
}
}
}
Implement the simulation of a biased 6-sided die which takes the values 1,2,3,4,5,6 with probabilities 1/8,1/12,1/8,1/12,1/12,1/
hjlf
Answer:
see explaination
Explanation:
import numpy as np
import matplotlib.pyplot as plt
a = [1, 2, 3, 4, 5, 6]
prob = [1.0/8.0, 1.0/12.0, 1.0/8.0, 1.0/12.0, 1.0/12.0, 1.0/2.0]
smls = 1000000
rolls = list(np.random.choice(a, smls, p=prob))
counts = [rolls.count(i) for i in a]
prob_exper = [float(counts[i])/1000000.0 for i in range(6)]
print("\nProbabilities from experiment : \n\n", prob_exper, end = "\n\n")
plt.hist(rolls)
plt.title("Histogram with counts")
plt.show()
check attachment output and histogram
Answer:
False ( B )
Explanation:
Of the seven IT infrastructure domains The USER domain was not at risk because the User Domain is not task with handling the sharing of data or Mutual communication between users in a Typical IT infrastructure.
The domain charged with such responsibility is The LAN domain because the LAN domain is charged with the sharing of information between the USERS and maintaining good mutual communication, and since the relationship has become sour, the sharing of information between the users will suffer the most and it will be at a high risk
