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trapecia [35]
3 years ago
6

20 Points PLEASE Hep .Factorize this h(t) = -16x^+72x ( negative 16 squared plus 72x )

Mathematics
2 answers:
stepladder [879]3 years ago
4 0

Answer:

-8x(2x - 9)

Step-by-step explanation:

-16x² + 72x

GCF = 8x

8x(16x² / 8x, -7x/8x)

-8x(2x - 9)

hope this helps!!

marta [7]3 years ago
3 0

The answer would be -8x(2x-9)

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You're going on a 1211-mile trip, and your car gets about 29 miles per gallon. Gas prices along your route average $3.40. Estima
Vilka [71]

Answer:

Using the estimate:

The car has to go for 1,200 miles but it consumes a gallon of gasoline for every 30 miles. The number of gallons it will need is therefore:

= 1,200 / 30

= 40 gallons

Each gallon costs $3.00 so the total cost is:

= 40 * 3

= $120

Without using the estimate:

The car has to go for 1,211 miles but it consumes a gallon of gasoline for every 29 miles. The number of gallons it will need is therefore:

= 1,211 / 29

= 41.76 gallons

Each gallon costs $3.40 so the total cost is:

= 41.76 * 3.40

= $‭141.98

<em>Using the estimate provides a lower cost of gasoline for the trip. </em>

3 0
3 years ago
Skylar's grades on four math tests are 85, 78, 77, and 69. What does Skylar need to score on the next test in order to have a me
olga_2 [115]
She needs to score a 91 on her next test because 85+78+77+69+91=400 and 400 divided by 5 gives you a mean of 80.
6 0
3 years ago
Simplify by using factoring: (2a+6b)(6b−2a)−(2a+6b)^2
GrogVix [38]

Answer:

-8a(a+3b)

Step-by-step explanation:

(2a+6b)(6b−2a)−(2a+6b)^2

(2a+6b) {(6b−2a)−(2a+6b)(2a+6b)}

2(a+3b) (6b-2a-2a-6b)

2(a+3b) (-4a)

-2(a+3b) x 4a

-2 x 4a (a+3b)

-8a(a+3b)

8 0
2 years ago
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
Read 2 more answers
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