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Komok [63]
4 years ago
6

Solve the equation for y 6y+x=8

Mathematics
2 answers:
Mama L [17]4 years ago
5 0

Answer: y=4x/3+1

Step-by-step explanation:

Igoryamba4 years ago
3 0

Answer:

y=4/3-1/6x

Step-by-step explanation:

1) subtract "x" from both sides:

6y=8-x

2)divide by 6 on both sides(EVERYTHING WILL BE DIVIDED BY 6)

6y/6=(8-x)/6

y=(8-x)/6

2)simplify:

y=4/3-x/6

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What is the area, in square units, of trapezoid ABCD shown below?
SOVA2 [1]

Given:

Trapezoid with bases 10 and 20, and height of the trapezoid is 6.

To find:

The area of the trapezoid.

Solution:

We know that the area of a trapezoid is:

A=\dfrac{1}{2}h(b_1+b_2)

Where, h is the height of the trapezoid and b_1,b_2 are bases of the trapezoid.

Putting h=6, b_1=10,b_2=20 in the above formula, we get

A=\dfrac{1}{2}(6)(10+20)

A=3(30)

A=90

The area of the trapezoid is 90 sq units. Therefore, the correct option is A.

7 0
2 years ago
Sara has 4 yellow beads and 3 green beads.how many beads does sara have
Neko [114]
Sarah has 7 beads all together
7 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
3 years ago
Solve the equation for w<br> 7w + 18 = 10w + 24
DochEvi [55]

Answer:

The answer is -2.

Step-by-step explanation:

7w + 18 = 10w + 24

7w = 10w + 6

-3w = 6

w = -2

6 0
3 years ago
Read 2 more answers
Can someone answer this question for me pls n thanks
allsm [11]

Answer:

Mean: 29.5;    Median: 26;    Modes: 25, 26

Step-by-step explanation:

Add 10+12+25+25+26+26+30+31+33+34+47+55 = 354

Then divide it by 12      354/12 = 29.5

Mode are numbers that appear most often which in this case are 2 numbers, 25 and 26.

8 0
2 years ago
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