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Pachacha [2.7K]
3 years ago
5

Days of the week and months of the year are capitalized in Spanish. a) True b) False

Spanish
2 answers:
stich3 [128]3 years ago
7 0

Answer:

False.

Explanation:

While we capitalize the days of the week and the months in English, the Spanish speakers do not capitalize them.  Hope this helped!

-Kirito

solmaris [256]3 years ago
6 0
True
trust me i’m hispanic
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Una carga esta a una distancia de 3.5 m de otra carga, las cuales tienen cargas de: q1 = 9.4x10-6 C y q2 = -7.6x10-3 C. Determin
lubasha [3.4K]

Answer:

La magnitud de la fuerza es de 52.487 N, la fuerza es de atracción en tanto que los signos de las cargas son opuestos entre sí.

Explanation:

La fuerza experimentada entre las dos partículas cargadas es de naturaleza electrostática. De acuerdo con la Ley de Coulomb, la fuerza electrostática es directamente proporcional a las cargas de las partículas e inversamente proporcional al cuadrado de la distancia entre las partículas, es decir:

F = \frac{\kappa \cdot q_{1}\cdot q_{2}}{r^{2}} (1)

Donde:

\kappa - Constante electrostática, en newton-metros cuadrados por coulomb cuadrado.

q_{1}, q_{2} - Magnitudes de las cargas de las partículas, en coulombs.

r - Distancia entre las partículas, en metros.

Si \kappa = 9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}, q_{1} = 9.4\times 10^{-6}\,C, q_{2} = 7.6\times 10^{-3}\,C y r = 3.5\,m, entonces la fuerza electrostática entre las partículas es:

F = \frac{\kappa \cdot q_{1}\cdot q_{2}}{r^{2}}

F = \frac{\left(9\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} \right) \cdot (9.4\times 10^{-6}\,C)\cdot (7.6\times 10^{-3}\,C)}{(3.5\,m)^{2}}

F = 52.487\,N

La magnitud de la fuerza es de 52.487 N, la fuerza es de atracción en tanto que los signos de las cargas son opuestos entre sí.

4 0
2 years ago
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