Given r<span>ectangle DEFG has vertices D(-6, -5) E(-6 -2) F(-2, -2) G(-2, -5).
Translation of rectangle DEFG by 3 units up will result in an image with the same x-coordinate and a y-coordinate obtained by adding 3 to the y-cordinates of the vertices of DEFG.
Thus a translation of 3 units up will result in rectangle D'E'F'G' with vertices D'(-6, -2), E'(-6, 1), F'(-2, 1), G'(-2, -2).
Assuming the rotation of 90° about the origin was done in the clockwise direction, this will result in an image having the verties obtained by interchanging the x-coordinate and the y-coordinate of the vertices of D'E'F'G' and then the sign of the y-coordinate is changed.
Thus, a rotation of 90° about the origin in the clockwise direction will result in the rectangle D"E"F"G" with vertices D"(-2, 6), E"(1, 6), F"(1, 2), G"(-2, 2).
Therefore, if r</span><span>ectangle
DEFG with vertices D(-6, -5) E(-6 -2) F(-2, -2) G(-2, -5) is
first translated 3 units up and then rotated 90° about the origin, the shape of the figure formed after this sequence of transformations is a rectangle with vertices </span><span>D"(-2, 6), E"(1, 6), F"(1, 2), G"(-2, 2).</span>
first, replace A by 5, and maintain the negative to the 5.
multiply (-5)^2.
nb: don't forget to maintain the bracket when multiplying. if you maintain the bracket, you'll get a positive number, but if you don't, you'll get a negative number.
To find the length of the ladder, you need to do Pythagorean theorem. 50^2 + 30^2 = x^2 2500 + 900 = x^2 x^2 =3400 x= square root of 3400 58.31 OR 10 root34
To find the angle: tan theta = opposite/adjacent 50/30 = 5/3 theta = tan inverse of 5/3 = 59.04
