Answer: Survival rate up to start of April = 76.67%
Explanation: size of colony = 150mice.
Size of colony in February =125mice.
Size of colony in march = 115 mice.
1. Survivorship rate in February
= Size of colony / size in February *100.
= 122 / 150 * 100
= 83.33% to the nearest hundredth
2. Survivorship rate in march
= Size of colony / size in march *100.
= 115/150 * 100
= 76.67% to the nearest hundredth.
Answer:
P = f(TLTL) = 0,16
H = f(TLTS) = 0,48
Q = f(TSTS) = 0,36
Explanation:
Hello!
The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).
The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.
In this case, let's say:
f(TL) = p
f(TS) = q
p + q = 1
Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:
TL= 0,4
TS= 0,6
Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.
P = f(TLTL)
H = f(TLTS)
Q = f(TSTS)
Also P + H + Q = 1
And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:



So, if the population is in balance:



Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:



I hope you have a SUPER day!
I think the answer for Q2 is D but i could be wrong. sorry if i am
Answer:
Cell wall and chloroplasts is correct option.
Explanation:
Hope it will help ^_^