Question

(2x3 + 2x2 + 2x) / (x2 + x + 1)

Answer 1

Answer:  2x

Step-by-step explanation:

Factor out the common term of 2x from the numerator, then cancel out the common factor from the numerator and denominator.

$\dfrac{2x^3+2x^2+2x}{x^2+x+1}\quad =\dfrac{2x(x^2+x+1)}{x^2+x+1}\quad =2x$

Answer 2

For this case we have:

$\frac {2x ^ 3 + 2x ^ 2 + 2x} {x ^ 2 + x + 1} =$

We have to:

$2x ^ 3 + 2x ^ 2 + 2x = 2x (x ^ 2 + x + 1)$

So, rewriting the expression we have:

$\frac {2x (x ^ 2 + x + 1)} {x ^ 2 + x + 1} =$

Simplifying similar terms of the numerator and denominator we have:$\frac {2x (x ^ 2 + x + 1)} {x ^ 2 + x + 1} = 2x$

Answer:

$2x$