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Ksju [112]
3 years ago
14

I need help on number two

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

2 y = 100

10 y = 20

20 y = 10

Step-by-step explanation:

To find the answer divide Y by X since y is 200 in the first and x is 1 divide 200 by the second one and you will find you answer.

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This figure is reflected across the x-axis, what is the orientation of the reflected figure?
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I am guessing it is the y axis ?
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3 years ago
Use the Ratio Test to determine whether the series is convergent or divergent. [infinity] n! 112n n = 1 Identify an. Correct: Yo
MakcuM [25]

Answer:

Step-by-step explanation:

Recall that the ratio test is stated as follows:

Given a series of the form \sum_{n=1}^{\infty} a_n let L=\lim_{n\to \infty}\left|\frac{a_{n+1}}{a_n}\right|

If L<1, then the series converge absolutely, if L>1, then the series diverge. If L fails to exist or L=1, then the test is inconclusive.

Consider the given series \sum_{n=1}^{\infty} n! \cdot 112n. In this case, a_n =n! \cdot 112n, so , consider the limit

\lim_{n\to\infty} \frac{(n+1)! 112 (n+1)}{n! 112 n} = \lim_{n\to\infty}\frac{(n+1)^2}{n}

Since the numerator has a greater exponent than the numerator, the limit is infinity, which is greater than one, hence, the series diverge by the ratio test

7 0
3 years ago
Alaska has a coastline of about 6.64 thousand miles. Florida has about 1.35 thousand miles of coast. How many times more does Al
zimovet [89]
Alaska has 4.91851852 thousand miles more than Florida coastline
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Read 2 more answers
Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of er
Vikentia [17]

Answer:

ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =69 represent the sample mean for the sample  

\mu population mean

s=4.0 represent the sample standard deviation

n=64 represent the sample size  

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

The sample mean \bar X have the following distribution:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

The margin of error for the sample mean is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since we have the sample standard deviation we can estimate the margin of error like this:

ME=t_{\alpha/2}\frac{s}{\sqrt{n}}

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025

We can find the degrees of freedom like this:

df=n-1=64-1=63

And we can find the critical value with the following code in excel for example: "=T.INV(0.025,63)" and we got:

t_{\alpha/2}=\pm 1.998

And the margin of error would be :

ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1

3 0
3 years ago
Will mark brainliest
Ede4ka [16]

Answer:

350

Step-by-step explanation:

7 0
2 years ago
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