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Ksju [112]
3 years ago
14

I need help on number two

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

2 y = 100

10 y = 20

20 y = 10

Step-by-step explanation:

To find the answer divide Y by X since y is 200 in the first and x is 1 divide 200 by the second one and you will find you answer.

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a plane can fly 7 miles per minute. the plane will fly 8 trips, and each trip is 810 miles. how many hours will the plane fly? s
Gnesinka [82]

Answer: 12 hours and 24 Minutes

Step-by-step explanation:

7*60 = 420

810/420 = 1.9285

93- 100 = 53-60

subtract 40 from 93.

1.53*8 = 12.24

Answer: 12 hours and 24 Minutes

3 0
4 years ago
If the area of a circle is 64 square meters then what is the radius
s2008m [1.1K]

Answer:

Radius = 4.51

Step-by-step explanation:

7 0
3 years ago
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Solve the combined inequality x + 3 > -5 and -4x ≥ -16 showing all of your work
ad-work [718]
Well for the first one you have to subtract 3 on both sides so that would make the equation x > -8 (because a negative subtracting a positive is basically a negative plus negative) and so your equations done.  For the second one you divide both ides by -4 so your equation would be x < 4 (the sign would be less then or qual to because you divided by a negative)
5 0
3 years ago
What is the height of the tree show all work
poizon [28]

Answer:

x=32.91

Step-by-step explanation:

Given: Triangle

Find: x

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Tan(35°)=x/47

x=tan(35)×47

x=0.7×47

x=32.91

Hope it helps!

3 0
3 years ago
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How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
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