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Ganezh [65]
3 years ago
12

What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard

Mathematics
1 answer:
Ahat [919]3 years ago
5 0

We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2

\text{Area of rectangle}=\frac{5}{8}\text{ yard}^2

Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

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Solve for x.
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Answer:

x = -4037/127

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

14x + 18 + x = -112(x + 36) + 13

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -112:                         14x + 18 + x = -112x - 4032 + 13
  2. Combine like terms:                15x + 18 = -112x - 4019
  3. Add 112x on both sides;          127x + 18 = -4019
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  5. Isolate <em>x</em>:                                   x = -4037/127
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