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Ganezh [65]
3 years ago
12

What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard

Mathematics
1 answer:
Ahat [919]3 years ago
5 0

We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2

\text{Area of rectangle}=\frac{5}{8}\text{ yard}^2

Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

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Step-by-step explanation:

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The table shows the relationship y = kx.
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3 years ago
Types of bonds are divided into three categories: good risk, medium risk, and poor risk. Assume that of a total of 11, 332 bonds
Alekssandra [29.7K]

Answer:

Probabilty of not poor= 0.75

Step-by-step explanation:

total of 11332 bonds.

7311 are good risk.

1182 are medium risk.

Poor risk

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= 11332-(7311+1182)

= 11332-8493

= 2839.

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Probabilty that the ball choosen at random is not poor= 1 - probability that the ball is poor

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3 0
3 years ago
Compare the fractions. 4/7 1/6.<br> a. &gt;<br> b. =<br> c.
BabaBlast [244]
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