Angle side Angle
parallel lines cut by a transversal form alternate interior angles
parallel lines are congruent
opposite angles are congruent ( angle D and angle B)
line AB is congruent to line BC
What exactly are partial quotients? Normal divisions says the answer is twenty three
The set A U B is represented by shading both circles A and B (also the overlapping region as well). Any point in set A U B will be in either A, B or both.
Answer:
FG = 16
Step-by-step explanation:
if df bisects <edg then triangles DFE and DFG are similar AAA
since DF is the same in both triangles triangles DFE and DFG are congruent
therefore FE = FG
n+5 = 2n-6
subtract n from each side
n-n+5 = 2n-6-n
5 = n-6
add 6 to each side
5+6 = n
n=11
FG = 2n-6
=2*11 -6
= 22-6
= 16
She can mostly add 35 and 9 and it will give you 44
