<h2>
<u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>
Given system of linear equations are ,
And we need to find the Solution of the linear equation . So let's Firstly number the equations .
<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>
=> 3 ( x + y ) = 2*3
=> 3x + 3y = 6
<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>
=> 3x + 3y -3y + y = 6 + 2
=> 4y = 8
=> y = 8/4
=> y = 2
<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>
=> x + y = 2
=> x + 2 = 2
=> x = 2- 2
=> x = 0
<h3>
<u>★</u><u> </u><u>Hence</u><u>
the required solution is ( 0 , 2 ) .</u></h3>
Answer:
<u>first graph:</u>
function.
Not one-one
onto
<u>Second graph:</u>
Function
one-one
not onto.
Step-by-step explanation:
We know that a graph is a function if any vertical line parallel to the y-axis should intersect the curve exactly once.
A graph is one-one if any horizontal line parallel to the x-axis or domain should intersect the curve atmost once.
and it is onto if any horizontal line parallel to the domain should intersect the curve atleast once.
Hence, from the <u>first graph:</u>
if we draw a vertical line parallel to the y-axis then it will intersect the graph exactly once. Hence, the graph is a function.
But it is not one-one since any horizontal line parallel to the domain will intersect the curve more than once.
But it is onto, since any horizontal line parallel to the domain will intersect the curve atleast once.
<u>Second graph</u>
It is a function since any vertical line parallel to the co-domain will intersect the curve exactly once.
It is not one-one since any horizontal line parallel to the x-axis does not intersect the graph atmost once.
It is not onto, since any horizontal line parallel to the domain will not intersect the curve atleast once.
For #6 draw a triangle between the points and find the middle by drawing the lines to the middle. There should be triangles within the triangles which finding the hypotenuses should be the same.
plug in the x for all of those to find y
Step-by-step explanation:
By Linear Pair Theorem,
110⁰ + 5x⁰ = 180⁰
5x⁰ = 70⁰ ------- (1)
x⁰ = 14⁰
We know that adding the angles of the triangle lying on the same side, equals the opposite exterior angle, i.e.,
5x⁰ + 40⁰ = 2y⁰
From 1,
70⁰ + 40⁰ = 2y⁰
110⁰ = 2y⁰
y⁰ = 55⁰
<em>Hope it helps :)</em>
