How do I write 3 2/3 in a from of a decimal?

The recipe for Perfect Purple Water says, "Mix 8 ml of blue water with 3 ml of red water." Jada mixes 24 ml of blue water with 9

cluponka [151]

Answer:Jada will get same shade as Perfect Purple Water

Step-by-step explanation:

STEP 1

To get the right recipe for Perfect purple water, every new mixture must have an equivalent ratio as the ideal mixture

The ideal mixture is given as

8ml blue water and 3 ml red water.

Step 2

Andre mixes 16ml blue water with 9ml red water

$\frac{8ml}{3ml}$ is not equivalent to $\frac{16ml}{9ml}$

Because dividing Andre's mixture by a common value will not give the equivalent ratio of the ideal recipe

$\frac{16ml}{9ml}$ $\frac{/}{/}$ $\frac{3}{3}$ = $\frac{5.3ml}{3ml}$

Jada mixes 24ml blue water with 9ml red water

$\frac{8ml}{3ml}$ is equivalent to $\frac{24ml}{9ml}$

Because dividing Jada's mixture by a common value gives the equivalent ratio of the ideal recipe

$\frac{24ml}{9ml}$ $\frac{/}{/}$ $\frac{3}{3}$ = $\frac{8ml}{3ml}$

This shows that Jada got the right recipe and will get same shade as Perfect Purple Water but in a higher quantity, 3 times the right recipe for Perfect Purple Water

7 0

3 years ago

Complete the congruence statement if CMH=PLF and DNO=AET (See photo for questions 1-8) (Please answer all 8 questions.).

Rus_ich [418]

Angle M = angle L
line MC = line LP
line DN = line AE
angle A = angle D
line FL = line HM
angle C = angle P
line TE = line ON
angle O = angle T

3 0

3 years ago

Show your work answer:v/7= 8

Kitty [74]

Answer:

V=56

Step-by-step explanation:

7x8=56

56/7=8

8 0

3 years ago

Read 2 more answers

The number of students who attended FPM in 2015 was 1380. In 2016, 1405 students attended FPM. what was the percent of change in

Fittoniya [83]

The percent of change in student enrollment is 1.81 % increase

Solution:

Given that, The number of students who attended FPM in 2015 was 1380

In 2016, 1405 students attended FPM

To find: Percent change

The percent change is given by formula:

$\text { percent change }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100$

If the result is positive, it is percent increase

If the result is negative, it is percent decrease

From given,

Initial value in 2015 = 1380

Final value in 2016 = 1405

Substituting the values in formula, we get

$\text { percent change }=\frac{1405-1380}{1380} \times 100\\\\\text { percent change }=\frac{25}{1380} \times 100\\\\\text { percent change }= 0.01811 \times 100\\\\\text { percent change }= 1.81$

Thus percent of change in student enrollment is 1.81 % increase

6 0

3 years ago

Need help please anyone?

poizon [28]

Ok so for part a we're going to use substitution, since both equations have y alone.

Step 1: Use substitution

y = x - 1 y = -x + 3

x - 1 = -x + 3

If you think about it, this makes sense. You're looking for the point where they intersect, and you know that the y coordinate for that point will be the same in both equations. Therefore, we can set the rest of the equations equal to each other. Now we just need to simplify.

Step 2: add x to each side

x - 1 + x = -x + 3 + x

The x's on the right cancel out so we get:

2x - 1 = 3

Step 4: Add 1 to each side

2x - 1 + 1 = 3 + 1

2x = 4

Step 5: Divide both sides by 2

2x/2 = 4/2

x = 2

Step 6: Plug this x value back into one of the original equations to find the y coordinate

y = x - 1

y = 2 - 1

y = 1

Therefore your answer to part a is (2,1)

I've graphed the solution and attached it. It shouldn't be too hard to replicate - just draw both lines and they should intersect at (2,1)

Hope that helps! If you need clarification or anything please feel free to ask :)

4 0

2 years ago