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3 years ago

I need help in this section.

Mathematics

1 answer:

Phoenix [80]3 years ago

6 0

Answer:

$\frac{1}{45}$

Step-by-step explanation:

There are

2 yellow

3 magenta

5 blue

marbles in the bag.

So total of 2 + 3 + 5 = 10 marbles

We have to multiply the probability of yellow on first pick by the probability of yellow on second pick (WITHOUT REPLACEMENT).

We denote P(Y1) as probability of yellow on first draw &

P(Y2) as probability of yellow on second draw

Thus,

P(Y1) = 2/10 = 1/5 [since 2 yellow and 10 total marbles]

Now,

P(Y2) = 1/9 [since now 1 yellow is taken out and NOT replaced, so we have 1 yellow remaining and total 9 marbles]

Now, we multiply:

P(Y1) * P(Y2) = 1/5 * 1/9 = 1/45

The probability is $\frac{1}{45}$

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3 years ago

When the members of a family discussed where their annual reunion should take place, they found that out of all the family mem

Doss [256]

Answer:

The total number of family members is 21.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of these sets.

I am going to say that:

-The set A represents those that would not go to a park.

-The set B represents those who would not go to a beach.

-The set C represents those who would not go to the family cottage.

The value d represents those who would go to all three places.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a are those that would only not go to a park, $A \cap B$ are those who would not got to a park or to the beach, $A \cap C$ are those who would not go to a park or to the famili cottage. And $A \cap B \cap C$ are those that would not go to any of these places.