Is the function h(x)=<br> -<br> 4x+7 linear or nonlinear?

I need help with my math, please?

jok3333 [9.3K]

Answer:

Step-by-step explanation:

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=8a%283b%2B6c-7c%29" id="TexFormula1" title="8a(3b+6c-7c)" alt="8a(3b+6c-7c)" align="absmiddle"

tino4ka555 [31]

Answer:

24ab-8ac

Step-by-step explanation:

Assuming you want to simplify it.

Original equation: 8a(3b+6c-7c)

Apply 8a to each variable in the paranthesis: (8a)(3b)+(8a)(6c)+(8a)(-7c)

After multiplication: 24ab+48ac-56ac

Combine like terms: 24ab-8ac

8 0

2 years ago

Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *

Luda [366]

Answer:

The answer to your question is $\frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1$

Step-by-step explanation:

Data

Foci (-2, 2) (4, 2)

Major axis = 10

Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

2c = 6

c = 6/2

c = 3

3.- Determine a

2a = 10

a = 10/2

a = 5

4.- Determine b using the Pythagorean theorem

a² = b² + c²

-Solve for b

b² = a² - c²

b² = 5² - 3²

b² = 25 - 9

b² = 16

b = 4

5.- Find the center (1, 2) From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

$\frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1$

$\frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E2%20%5Cleft%28%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%20

Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

$\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx$

Let $f(x) = \sqrt{1 + x^3}$ . Compute the inverse:

$f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}$

and we immediately notice that $f^{-1}(x+1)=\sqrt[3]{x^2+2x}$ .

So, we can write the given integral as

$\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx$

Splitting up terms and replacing $x \to x-1$ in the first integral, we get

$\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}$

7 0

2 years ago

HELP!! I will award brainliest!!!

Ugo [173]

Answer: c

Step-by-step explanation:

5 0

2 years ago

Is the function h(x)= - 4x+7 linear or nonlinear?