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2 years ago

PLLLZZ HELP!!!!

Mathematics

1 answer:

topjm [15]2 years ago

8 0

Answer:

3. A quadrilateral with each side length 4 cm

Step-by-step explanation:

We need to understand what is a unique polygon?

<em>It means all regular polygons with the same number of sides are similar.</em>

1.A triangle with angles 30 degrees, 60 degrees, and 90 degrees

It is an right triangle, so the 3 sides are not simillar, so it is wrong

2. A triangle with side lengths 5 cm, 4 cm, and 3 cm

It is a triangle with the 3 sides are not simillar, so it is wrong

3. A quadrilateral with each side length 4 cm

It is an square with the 4 sides are simillar, so it is true

4. A triangle with side lengths 7 cm and 8 cm and a 40-degree angle

It is a triangle with the 3 sides are not simillar, so it is wrong

Hence, we choose 3.

You might be interested in

An obtuse triangle has two angles 45 n 18 ,and a third unknown angle theta what's the value of the unknown angle

zlopas [31]

<u>Answer:</u>

An obtuse triangle has two angles 45 and 18. The value of the unknown angle is $117^{\circ}$

<u>Solution:</u>

Given that two angles of an obtuse triangle is 45 and 18.

Third angle is θ

We are asked to find the value of third unknown angle theta

According to <em>angle sum property of triangle</em>, sum of three angles of triangle is $180^{\circ}$

This means in our case sum of 45, 18 and θ should be $180^{\circ}$

$\begin{array}{l}{=>45+18+\theta=180} \\ {=>\theta=180-63=117^{\circ}}\end{array}$

Hence value of unknown third angle of an obtuse triangle is $117^{\circ}$

7 0

2 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

Read more about the center of mass.

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8 0

1 year ago

Hello can anyone give me the full answer to this step by step?

Andre45 [30]

Answer:

1. f = 16 degrees

2. h = 10 degrees

Step-by-step explanation:

1. f = (180 - 67+46 - 4) / 4

2. h = (180 - 60 + 90) / 3

5 0

2 years ago

Read 2 more answers

2-7-4q+8q plz help me

Lunna [17]

Noooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

7 0

2 years ago

PLEASE HELP ASAP WILL MARK BRAINLIEST!!

Papessa [141]

Answer:

Prime.

Step-by-step explanation:

$x^2-7x+8\\$

First let's multiply our outer coefficients in this case 1 and 8, so we have 1x8=8. Now the point of this is to get the factors of 8 and see if we can get that middle term -7. Factors of 8 are 1x8, 2x4 and that's it. From there I notice that -8+1 = -7 and so:

$x^2-7x+8 = x^2-8x+x+8 = x(x-8)+(x+8)$

Notice that the (x-8) and (x+8) are not the same factors, therefore the factors are not any of those answer choices and so it's prime. You can calculate the factors by using the quadratic formula, however I think that is beyond the scope of this question.

7 0

2 years ago