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3 years ago

On a trip, the fare was 50¢ for each adult and 25¢ for each child. If 30 passengers paid $12.25, how many adults and

Mathematics

2 answers:

Viefleur [7K]3 years ago

8 0

Answer:

50x+ 25(30 - x) = 1225

Step-by-step explanation:

Data:

The bus fare = $ 50 c

Thus, x passengers pay = x($ 50c)

There are 30 children. So, out of the 30 passengers, the children pay = (30 - x) x $ 25c

Therefore, the total paid:

50x + (30 - x)25 = 225

50x + 25 (30-x) = 225

WARRIOR [948]3 years ago

3 0

Answer:

The number of adult is 19 and number of children is 11

Solution:

Given that there were total 30 passengers.

Let the number of adult be x.

Therefore, number of children = 30-x

It is given that the fare for adult = 50$

The fare for x adults will be $50 \times (x)$

It is also given that the fare for children is 25$

The fare for (30-x) children = $25 \times (30-x)$

Now according to the question, 30 passengers paid $1225

50x + 25(30-x) = 1225

50x + 750 - 25x = 1225

25x = 1225-750

25x = 475

$x = \frac{475}{25}$

x = 19

Therefore number of adult = 19

Number of children = 30-19 = 11

From the given below equations, 25x + 50x = 30(1225) cannot be used to solve the problem.

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