Answer:
b) 2.45
Step-by-step explanation:
The Euclidean distance in 3-space is the root of the sum of the squares of the x-, y-, and z-differences between the points.
<h3>Application</h3>
For the given points ...
The distance between x and y is ...
The volume of the space not filled by the sphere is the difference between the volume of a cube with edge length 6 inches and the volume of a sphere with radius 3 inches.
<h3><u>Cube</u></h3>
The volume of a cube of edge length s is
... V = s³
When the edge length is 6 in, the volume is
... V = (6 in)³ = 216 in³
<h3><u>Sphere</u></h3>
The volume of a sphere with radius r is
... V = (4/3)π·r³
When the radius is 3 in, the volume is
... V = (4/3)π·(3 in)³ = 36π in³
<h3><u>Space</u></h3>
Then the volume of the space between the cube and the sphere is
... Vcube - Vsphere = 216 in³ - 36π in³ ≈ 102.9 in³ . . . . corresponding to choice C
4a=20⇒a=5
we know diagonals are perpendicular. if u look at one of the right triangles, you can see that for hypotenuse to be 5, the legs have to be 4 and 3 to satisfy the given ratio 4:3.
so, diagonals are 8 and 6 as we know that diagonals bisect each other.
Area=8*6/2=24
2(2)2(3)2(4)=192 because you're multiplying everything together in order to find your answer and also because the variables which are the letters represent the numbers that need to be multiplied idk if that made sense but that's the answer lol
Answer:
16
Step-by-step explanation:
To solve a quadratic equation by using the completing the square method, the coefficient of the square term i.e x² must be one (1).
Therefore, we would have to first make the coefficient of x² to be equal to 1.
4x² + 24x + 8 = 32
We would simplify the equation;
4x² + 24x = 32 - 8
4x² + 24x = 24
Divide all through by 4;
x² + 8x = 24
The value to be added = (8/2)² = 4² = 16
x² + 8x + 16 = 8 + 16
x² + 4x + 4x + 16 = 24
x(x + 4) + 4(x + 4) = 24
(x + 4)² = 24
Taking the square root of both sides;
x + 4 = ± 4.9
x = -4 ± 4.9
x = -4 + 4.9 = 0.9
or
x = -4 - 4.9 = - 8.9
<em>Therefore, 16 must be added to solve the quadratic equation by completing the square method. </em>
