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stiks02 [169]
3 years ago
15

Find the nonpermissible replacement for a in -3/4a

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
This would be 0  because -3 / 4*0  = -3/0 is indeterminate.
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basically i need help trying to learn .. um ... i ... so basically what i’m asking is how.. why.... uh .. sorry i .. so overall
igor_vitrenko [27]
Can u find them ?????????????????????
4 0
3 years ago
The heights of a maple tree and a cherry tree have a ratio of 5:2. If the maple tree grew 20 cm and 20 cm was cut off the top of
elena-14-01-66 [18.8K]
Let x be the <span>heights of a maple tree and y be the height of the cherry tree.
We know: 
</span>\frac{x}{y} = \frac{5}{2}
<span>The new ratio is obtained like this:
</span>\frac{x+20}{y-20} = \frac{3}{1}.
From the above equation we get x= (y-20)\frac{3}{1} -20.
then \frac{ (y-20)\frac{3}{1} -20}{y} = \frac{5}{2}
Solving the above equation for y we get: y=160
So x=400
So the first tree is (400-160=240) more taller than cherry tree. 
7 0
3 years ago
Plz help me get the right answer ASAP please
Ierofanga [76]
<h2>Greetings!</h2><h3>When expanding brackets, you simply multiply whatever is inside the brackets by what is outside:</h3>

(7x * x) + (7x * 20)

<h3>Which would result in the answer being:</h3>

7x^{2} + 140x


<h2>Hope this helps!</h2>
5 0
3 years ago
Read 2 more answers
Answer Choices
sasho [114]

Answer:

c) only Anne

Step-by-step explanation:

I just did the test. Hope this helps! : )

4 0
3 years ago
In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the
ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

P(A) = 0.01 , P(B) = 0.02

We also know the probability that the memory and the hard drive fail simultaneously given by:

P(A \cap B) = 0.0014

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

P(A \cap B) = P(A) *P(B)

For this case we have that:

P(A) *P(B) = 0.01*0.02= 0.0002

And we see that 0.0002 \neq P(A \cap B)

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0
3 years ago
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