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3 years ago

How does a digit in the ten thousand place compare to adigit in the thousand

1 answer:

7 0

A digit in the ten thousand place is 10x times larger than a digit in the thousands place.
We can see that here- 1,000 x 10 = 10,000

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Please help <br><br>the question is beloww

madam [21]

Answer:

-8

Step-by-step explanation:

(x-3y=136) + (18x+3y=288) We collect both processes to make y's disappear

19x=-152

x=-8

5 0

3 years ago

A player shoots a basketball from a height of 6 feet. The equation, h = -16t^2 + 25t + 6, gives the height, h , of the basketbal

noname [10]

Answer:

$\boxed {\boxed {\sf 7.5 \ feet}}$

Step-by-step explanation:

We are given this function for the height (h) after t seconds:

$h=-16t^2+25t+6$

Seconds is t and we want to find the height after 1.5 seconds. Plug 1.5 in for t.

$h= -16(1.5)^2+25(1.5)+6$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Solve the exponent first.

(1.5)²= 1.5*1.5=2.25

$h= -16(2.25)+25(1.5)+6$

Multiply.

$h= -36+25(1.5)+6$

$h= -36+37.5+6$

Add.

$h=1.5+6=7.5$

This is already rounded to the nearest tenth, so it is the answer.

After 1.5 seconds, the basketball is at a height of 7.5 feet.

6 0

3 years ago

Over which interval is the graph of f(x) = -X2 + 3<br> 8 increasing?

Pepsi [2]

Yea because it’s increasing

6 0

4 years ago

To find the area of a trapezoid use the expression 1/2h (b1 + b2), where h represents the height b1 represents the length of the

lana [24]

Answer:

7 ft²

Step-by-step explanation:

The formula for this is given in the problem

Plug in the given values

1/2 * 2 (4+3)

1*7

7 ft²

7 0

3 years ago

Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.

Sonja [21]

<h3>Answer: Rhombus</h3>

======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\$

Segment AB is exactly $\sqrt{17}$ units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2) = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\$

Segment AB has a slope of 1/4.

Do the same for BC

$B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2) = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\$

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

4 0

2 years ago

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