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zysi [14]
3 years ago
5

How can you write -1/4x-9 on a graph​

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

Slope : -1/4

y-intercept : -9

x... 0 , 1

y... -9 , -37/4

Step-by-step explanation: Graph the line using the slope and y-intercept, or two points. GRAPH IS DOWN BELOW!

Hope this helps you out.

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leos oil field supply can deliver enough pipe valves to Valo Oil Company to fill their storeroom in 8 hours. valo oil compamy ca
DedPeter [7]
The answer would be ooo ahhhh eeee wala wala bang bang
6 0
3 years ago
Given h(x) = –2 – 3, find h(-6).
igomit [66]

Answer

3

Step-by-step explanation:

h(-6)=-(-6)-3

h(-6)=6-3

h(-6)=3

4 0
3 years ago
A rectangle has a perimeter of 48 ft. The length and width are scaled by a factor 1.5.
prohojiy [21]

Answer: 75

Step-by-step explanation:

when increased in scale,

both sides are multiplied by the factor which is 1.5.

72 =1.5(2L+2W)

Mark me as brainliest

7 0
3 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
Write a third-degree polynomial function whose zeros are 1, −3, and 4.
WARRIOR [948]
Recall that zeroes can be transformed into factors by subtracting them from x. This gives us the following factors:

(x - 1)(x + 3)(x - 4)

Now, if you multiply the first two factors together, you get the following:

(x² + 2x - 3)

Multiply that by the last factor, (x - 4), and you get this:

(x³ + 2x² - 3x - 4x² - 8x + 12)

This can be simplified:

(x³ - 2x² - 11x + 12)

And there's your final answer. Hope this helped!


8 0
3 years ago
Read 2 more answers
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