Question

For an arithmetic sequence that sums to 1485 it is known that the first term equals 6 and the last term equals 93 algebraically determine the number of terms summed in this series

Answer 1

Answer:

30

Step-by-step explanation:

s_{n}=\frac{a+l}{2}=n

first term=a

last term=l

number of terms=n

1485=\frac{6+93}{2}n

99 n=1485×2=2970

n=2970/99=270/9=30

number of terms=30