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Bezzdna [24]
4 years ago
4

Represent 56 ÷ 8 = 7 using subtraction. Explain your reasoning.

Mathematics
1 answer:
katrin2010 [14]4 years ago
6 0

Answer:

56\div 8=7

Step-by-step explanation:

The relationship of division and subtraction:

If a\div b=c then a-bc=0            (Definition 1)

The given equation is

56\div 8=7

We need to prove this by subtraction.

Let 56\div 8=x

Here, a= 56 is dividend, b=8 is divisor and c=7 is quotient.

56-8=48    (1st time)

48-8=40    (2nd time)

40-8=32    (3rd time)

32-8=24    (4th time)

24-8=16    (5th time)

16-8=8    (6th time)

8-8=0    (7th time)

It means we need to subtract 8 (total 7 times) from 56 to get 0.

56-8\times 7=0

Using definition (1) , we get

56\div 8=7

Hence proved.

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Answer:

-9x-2y-24

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-x-24-8x-2y

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-x= -1x, so -x-8x = -9x

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If x=-3 when y=7,find x when y=-7
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3 years ago
Identify all the lines on the graph with unit rates that are less than 2 and greater than the unit rate of the relationship in t
harina [27]

Answer:

  • line 3
  • line 4

Step-by-step explanation:

The "unit rate" is the slope of the line, or the ratio of change in y to change in x.

__

The "unit rate" of the relationship in the table can be found from the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (16 -8)/(14 -7) = 8/7

The slopes of the various lines are conveniently found using the fact that they all terminate on grid points with y=6, and they all go through the origin. Their slope is the ratio of 6 to the x-coordinate of the termination point:

  line 1: 6/2 = 3 . . . . slope not < 2

  line 2: 6/3 = 2 . . . . slope not < 2

  line 3: 6/4 = 3/2 . . . . slope < 2, > 8/7

  line 4: 6/5 . . . . slope < 2, > 8/7

  line 5: 6/6 = 1 . . . . slope not > 8/7

Lines 3 and 4 have slopes in the required range.

_____

<em>Alternate solution</em>

We can find the values of x corresponding to the limits on slope when y = 6. This lets us compare the given lines to the desired range of slope in a fairly direct way.

For the proportional relations shown,

  y = mx

Then x = y/m, and we have, for y=6, ...

  x = 6/2 = 3 . . . . upper limit on slope

  x = 6/(8/7) = 42/8 = 5 1/4 . . . . lower limit on slope

The lines that terminate at points with y=6 and 3 < x < 5 1/4 are ...

  lines 3 and line 4

4 0
2 years ago
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