From what you’re given, you know that , for some constant a. From that, you know that –2 + a = –b, and that –2a = b.
Multiply that second equation by –1, and then you can do some solvin’.
–2 + a = –<span>b
</span>2a = –b
–2 + a = 2<span>a
</span>–2 = a
Answer: The right hand limit is 4
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Start on the right side of the value x = 2. In other words, start at some value larger than 2, say x = 4. Starting at x = 4, move closer to x = 2. Move as close as you can. The closer x gets to 2, the closer y gets to 4. You'll never actually get to x = 2 or y = 4 because of the hole. However, the right-hand limiting value is 4 assuming you can keep getting closer and closer.
Note: if you approach x = 2 from the left side, you arrive at a different y value So this suggests that overall, the limit at x = 2 doesn't exist. But the right hand limit (RHL) does exist as described above.
5g + 3(-7 + 5g) = 1 - g
5g - 21 + 15g = 1 - g
20g - 21 = 1 - g
20g + g = 1 + 21
21g = 22
g = 22/21 <===
Answer:
-(4,-3)
Step-by-step explanation:
You need to find the slope from point o to b, and then multiply it three times to get to b prime.
Answer:
Step-by-step explanation:
Given
Required
Determine the coordinate of the 4th point
From the given parameters, we can see that the rectangle is either horizontal or vertical.
This is because:
and
To calculate the fourth point, we simply make use of:
and 
Substitute 1.5 for x2 in
Substitute -2 1/2 for y3 in 
Hence, the 4th point is:
