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Elenna [48]
3 years ago
6

How to divide 43.75 and 3.5

Mathematics
1 answer:
Alona [7]3 years ago
4 0
\dfrac{43.75}{3.5} = 12.5.<span>
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add 7. double the result. subtract 8. divide by 2. su tract the orginial selected number 1st nuber is 3 second number is 4 the t
sertanlavr [38]
Hi,


The equation looks like this...

n + 7 \times 2 - 8 \div 2 \\ 3 + 7 \times 2 - 8 \div 2 = 3 + 14 - 4 = 13 \\ 4 + 7 \times 2 - 8 \div 2 = 4 + 14 - 4 = 14 \\ 9 + 7 \times 2 - 8 \div 2 = 9 + 14 - 4 = 19 \\ 12 + 7 \times 2 - 8 \div 2 = 12 + 14 - 4 = 22

Hope this helps.
r3t40
8 0
3 years ago
CE and FH are parallel lines.<br><br> Which angles are supplementary angles?
nadya68 [22]

Answer:

<CDG and <CDB are supplementary angles.

6 0
3 years ago
Read 2 more answers
Please help!!
Rama09 [41]
The associative property of addition is pretty much just any numbers in place of these: a + (b + c) = (a + b) + c. Therefore, your answer would be d) (6 + 1) + 9 = 6 + (1 + 9)
6 0
3 years ago
A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o
Komok [63]

Answer:  Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}} , where \overline{x} = sample mean, n= sample size, s= sample standard deviation, t_{\alpha/2} = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05

Critical t-value : t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622

So, the 95 percent confidence interval estimate for the​ mean :

242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)

The 95 percent confidence interval estimate for the​ mean:(190.14, 295.06)

8 0
3 years ago
Linda needs 20 gallons of juice that has 75%fruit juice. she has a mixture that has 80% fruit juice and another mixtures that ha
suter [353]
Linda should use ...
  15 gallons of 80% juice
  5 gallons of 60% juice

_____
Let g represent the number of gallons of 80% juice needed. Then (20-g) is the number of gallons of 60% juice Linda will use. The amount of juice in the mixture can be written as
  0.80g +0.60(20 -g) = 0.75×20
  0.20g = 20(0.75 -0.60) = 20×0.15
  g = 20×0.15/0.20 = 15
The amount of 80% juice needed is 15 gallons, so 5 gallons of 60% juice are needed.
5 0
3 years ago
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