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3 years ago

7

Graphing sinusoidal functions I really need help.

1 answer:

Zielflug [23.3K]3 years ago

3 0

Answer: With the following g<span>iven the formula of a </span>sinusoidal function<span> of the form a*f(bx)+d, you can draw its </span>graph with this information.

Hope this helps!

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Can someone answer 6???

sergeinik [125]

Answer:

c

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the side length, in inches, of the pets

tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is $4x-5$ inches

Step-by-step explanation:

Given

Area of the square of design = $16x^{2} -40x+25$

First we find the roots of equation $16x^{2} -40x+25=0$

The roots of the quadratic equation $ax^{2} +bx^{2} +c=0$ are given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where $a=16, b=-40, c=25$

$x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}$

$x=\frac{40\pm\sqrt{1600-1600}}{32}$

$x=\frac{40\pm\sqrt{0}}{32}$

$x=\frac{40}{32}$

$x=\frac{5}{4}$

$4x=5\\4x-5=0$

That is, the factors of the polynomial $16x^{2} -40x+25$ are $4x-5$ and $4x-5$ .

So, Area of the square design = $16x^{2} -40x+25$ = $(4x-5)^{2}$

Area of a square = Length^2

Thus, the length of the sign is $4x-5$ inches

7 0

3 years ago

The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a

Alisiya [41]

I donu im just a kid that runs track. ahahahhahhahahha and plays roblox hahahahh

7 0

3 years ago

Under a translation of 5 units up and 2 units to the left, the point (3,4) will become

Vedmedyk [2.9K]

The point would become (8,2)
3+5=8
4-2=2

4 0

3 years ago

A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi

bearhunter [10]

Answer:

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

Step-by-step explanation:

For this case we have the following info:

$n =700$ represent the sample size

$X= 305$ represent the number of employees that earn more than 50000

$\hat p=\frac{305}{700}= 0.436$

We want to test the following hypothesis:

Nul hyp. $p \leq 0.4$

Alternative hyp : $p>0.4$

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

And the p value would be given by:

$p_v = P(z>1.922)= 0.0274$

4 0

3 years ago