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Sati [7]
3 years ago
9

2) m_A = 68°, c = 27, b = 25

Mathematics
1 answer:
V125BC [204]3 years ago
7 0
Hi, what’s your question?
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WILL MARK BRAINLIEST IF GOTTEN RIGHT!!!!
nikdorinn [45]

Answer:

C both line and point symmetry

Step-by-step explanation:

6 0
3 years ago
Suppose that a rectangular picture is surrounded by a frame of uniform width of x
user100 [1]

Answer:

Ok so the area of the frame is 18*12 = 216cm^2

Let’s suppose the width of the frame is x

The total area (painting and frame) is (2x+18)(2x+12) and this is equal to 432

4x^2 + 60x + 216 = 432

4x^2 + 60x - 216 = 0

x^2 + 15x - 54 = 0

(x+18)(x-3) = 0

Therefore x = {-18,3}

Since width of the frame has to be positive, the width has to be 3cm Step-

i hope i helped!

3 0
3 years ago
All the numbers from 1 to 100 that have 13 as a factor
Marrrta [24]
26, 39, 52, 65, 78, 91
3 0
4 years ago
Y 5x=2<br><br> What are the coordinates
Brums [2.3K]

Answer:move -5x to the right becomes 5x

Y=5X+2

When x =1 5(1)+2= 7 for Y

When X=2 5(2)+2= 12 for Y

When X =-1 5[-1)+2/ -3

Coordinates (1,7).(2,12)(-1,-3)

Step-by-step explanation:

3 0
3 years ago
2 planes leave the airport at the same time. their speeds are 140 mph and 170 mph and the angle between their courses is 25 degr
Damm [24]

Answer:

183.27miles

Step-by-step explanation:

Note that we are considering two planes.

Plane 1

Speed = 140 mph

Time = 2.5 hours

Distance = ?

Speed = distance/time

140 mph = distance/2.5hrs

Distance = 140×2.5

= 350miles

Plane 2

Speed = 170 mph

Time = 2.5 hours

Distance = ?

Speed = distance/time

170 mph = distance/2.5hrs

Distance = 170×2.5

= 425miles

The angle between side is 25 degree

From cosine rule

c^2 = a^2 + b^2 − 2abcos(tetha)

Where a = 350

b = 425miles

c^2 = 350^2+425^2-2(350×425)(cos25)

c^2 = 122500+180625-297500(0.906)

c^2 = 303125-269535

c^2 = 33590

C = √33590

C = 183.27miles

The distance they flew apart after 2.5hrs is 183.27miles

5 0
3 years ago
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