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3 years ago

12

Please help meASAP And show any work possible.

1 answer:

lubasha [3.4K]3 years ago

7 0

Answer:

A is the answer you have to multiply them by 8 and you get a as an answer.....

Love you!!!!!!.

Step-by-step explanation:

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246000 in scientific notation

atroni [7]

Answer:

2.46 x 10⁵

Step-by-step explanation:

7 0

3 years ago

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Matt bought a home in 2001 and paid $150,000 for it. He sold the home for $450,000. How much of the profit on his home will be t

butalik [34]

Answer:

profit to be taxable will be $300,000

Step-by-step explanation:

Matt home cost = $150,000

Matt sold his home for = $450,000

so,

cost price will be $150,000

selling price will be $450,000

profit = selling price - cost price

profit = $450,000 - $150,000

profit = $300,000

hence the taxable amount for his home this year will be $300,000

7 0

3 years ago

The expression 2^3x4^2 is equivalent to

Sav [38]

Answer:48

Step-by-step explanation:

2x3=6x4x2=48

3 0

3 years ago

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Determine if the relation is a function if so state the domain and range

Sedaia [141]

Answer:

Function - Yes

Domain - [-3,0,3,4]

Range - [1,2,2,5]

Step-by-step explanation:

In a function, x-values cannot repeat and in this relation, x's do not repeat, therefore it is a function. The domain is the x-values on the graph from least to greatest; so to find the domain, simply take the first value of each coordinate and order them from least to greatest. Then, the range is the y-values, so to find the range take the second value from each coordinate and order them from least to greatest.

8 0

2 years ago

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago