12 cm high is about 4.7 inches high
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
The picture is white I can’t help you sorry
Exponent rules : (a^m)^n = a^(mn) and a^0 = 1
(4^9)^5 * 4^0 =
4^45 * 1 =
4^45 <==
Answer:
9
Step-by-step explanation:
|9| = 9
Absolute value is distance from zero. 9 is 9 away from 0. BRAINLIEST? :')
