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lisabon 2012 [21]
3 years ago
11

Determine the equation of a line that has an x-intercept of −2 and a y-intercept of −5.

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Y=5/-2 -5

Slope=5/-2 because -2-0=-2 and 0-(-5) = 5

Y intercept is -5

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amy is building a house. the basement floor is at -15 feet. the roof of the house is above the ground 25 feet. express the compa
Deffense [45]

Answer:  375 sq.ft

Step-by-step explanation:

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3 years ago
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Amarathon is about 26 miles long. Which of these shows how to convert 26 miles to feet?
Vesna [10]

Answer: the third one down

26 miles times 5,280 feet

Step-by-step explanation:

Look at the units. Miles over miles will cancel, leaving feet... 1 mile is 5,280 feet, because a mile is bigger than a foot, and there are 5,280 feet per 1 mile.

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Anything can solve this
prohojiy [21]

Answer:

64.87° = 65°{ to the nearest degree}

Step-by-step explanation:

From the figure Catherine is standing 105m from the point B where the Ballon is; this description fits a= 105 m from the diagram.

Similarly Aisha is standing 95m from the point B where the Ballon is; this description fits c= 95 m from the diagram

A = ? ( The angle of elevation of Aisha towards the balloon)

C = 55°

From Sine rule

It states that the sine of an angle divided by its corresponding side is equal for all corresponding angles and sides along the triangle.

This is expressed mathematically as;

Sin A/ a= SinB/ b= SinC/c

We take the pairs of relevance;

Sin A/ a = SinC/c

There SinA = SinC/c × a

=Sin55/95 × 105

= 0.9053

A = Sin^(-1)[0.9053]

A = 64.87° = 65°{ to the nearest degree}

6 0
3 years ago
An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
The irregular figure on the left has been decomposed into the figures on the right.
shusha [124]

Answer:

The density of the material must be at least 1.5 g/cm³.

Step-by-step explanation:

c

7 0
3 years ago
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