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Dennis_Churaev [7]
4 years ago
15

What is the range and domain of the function : y= sqrt(x) -5 ... Can you please explain? Thanks btw the square root is only over

the x
Mathematics
2 answers:
alukav5142 [94]4 years ago
6 0

Answer:

Step-by-step explanation:

The answer is y> =-5

Likurg_2 [28]4 years ago
3 0
Okay so basically domain =input and range =output. you can never have a negative number underneath the square root sign because it will make the answer imaginary (i), unless you are on that concept. Therefore the range is any number greater than 0. -> all real numbers greater than or = 0

for the range if you input 0 as x you will get -5, so any number you input after 0 will be greater than -5. so range is all real numbers greater than or equal to -5. 
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-2(bx - 5) = 16<br><br> What’s does b and x equal?
horrorfan [7]
To solve this problem you must apply the proccedure shown below:
 You have the following equation given in the problem above:
 <span>-2(bx - 5) = 16
</span> When you solve for bx, you have:
 <span>-2(bx - 5) = 16
 -2bx-10=16
 -2bx=26
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 bx=-13

 When you solve for b, you obtain:
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 When yoo solve for x:
 </span>2bx=26
 x=-(26/2b)<span>

 </span>
3 0
3 years ago
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