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Gala2k [10]
3 years ago
9

_____ is amount of “ground” an object moves from its starting point and ______ is how much “ground” and object covers in total.

Physics
2 answers:
laiz [17]3 years ago
7 0

Displacement is the amount of "ground" and object moves from it starting point and distance is how much "ground" an object covers in total. Displacement by definition is moving of something from its place or position and distance by definition is the amount of space between two things (in this case the starting position and ending position).ΥΤ-ΤΟΝΙХWΙLSΟΝ

Reil [10]3 years ago
7 0

The key word in the first statement is AMOUNT of "ground" so the quantity but not the direction is important. So the first answer is Distance. Displacement  is how much “ground” and object covers in total.


The answer is B.


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below

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A 7.3 cm diameter loop of wire is initially oriented so that its plane is perpendicular to a magnetic field of 0.61 T pointing u
kenny6666 [7]

Answer:

induced emf =  28.65 mV

Explanation:

given data

diameter = 7.3 cm

magnetic field = 0.61

time period = 0.13 s

to find out

magnitude of the induced emf

solution

we know radius is diameter / 2

radius = 7.3 / 2

radius = 3.65 m

so induced emf is dπ/dt  = Adb/dt

induced emf =  A × ΔB / Δt

induced emf =  πr² × ΔB / Δt

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3 0
3 years ago
Consider the numbers 23.68 and 4.12. The sum of these numbers has ____ significant figures, and the product of these numbers has
damaskus [11]

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3 years ago
What is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then
Sedbober [7]

Answer:

x=(0.088m)\cos(\sqrt{\frac{k}{m} }  t)

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Now, since the spring starts stretched at its maximum, the appropriate function to use is the positive cosine in the equation of simple harmonic motion:

x=A\cos(\omega t)

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x=(0.088m)\cos(\omega t)

or

x=(0.088m)\cos(\sqrt{\frac{k}{m} }  t)

7 0
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