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VikaD [51]
3 years ago
8

You are given two infinite, parallel wires each carrying current I. The wires are separated by a distance d, and the current in

the two wires is flowing in the same direction. This problem concerns the force per unit length between the wires. What is the force per unit length F/L between the two wires?Express your answer in terms of I, d, and constants such as μ0 and π.
Physics
1 answer:
hoa [83]3 years ago
6 0

Answer:F/L = μ0*I²/2πd

Explanation:

Both wires carries current of the value (I) and are separated by the distance (d).

The length of both wires is (L).

The first wire creates a magnetic field of the magnitude according to Bio-savart law

B=(Uo * I)/2πd

This magnetic field has the ability to exert a force F on the second wire.

This force (F) is given as

F=BIL* sin θ

θ here is 90 because the magnetic field is perpendicular to the length of the second wire.

Thus the value of sin 90 = 1

Hence F= BIL

But B=(Uo * I)/2πd.

We have that F= B=[(Uo * I)/2πd] x IL

Thus we have that F= [Uo* I²/2πd] x L

By rearranging, and bringing L to the left hand side of the equation, we have that

F/L = [Uo* I²/2πd]

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A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or sh
zalisa [80]

Complete question:

Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a "crumple zone" in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 m as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. In contrast,  a passenger not wearing a seat belt or using an air bag decelerates over a distance of 5mm.

(a) A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys.

Answer:

The net force on the person as the air bad deploys is -6750 N backwards

Explanation:

Given;

mass of the passenger, m = 60 kg

velocity of the car at impact, u = 15 m/s

final velocity of the car after impact, v = 0

distance moved as the front of the car crumples, s = 1 m

First, calculate the acceleration of the car at impact;

v² = u² + 2as

0² = 15² + (2 x 1)a

0 = 225 + 2a

2a = -225

a = -225 / 2

a = -112.5 m/s²

The net force on the person;

F = ma

F = 60 (-112.5)

F = -6750 N backwards

Therefore, the net force on the person as the air bad deploys is -6750 N backwards

4 0
3 years ago
An elevator is moving downward when someone presses the emergency stop button. The elevator comes to rest a short time later. Gi
OLga [1]

Answer:

<em>Answer:  - , + </em>

Explanation:

<u>Velocity and Acceleration </u>

In general terms, velocity and acceleration in the plane are both vectors with two components. They don't have 'sign' but magnitude and direction. If we know motion is restricted to a simple line, then we can define the positive and negative references.

In vertical motion, the positive reference is commonly pointed upwards, but if we chose the opposite way, the results shouldn't change in magnitude, just their signs. Let's choose like proposed, the positive direction upwards.

Since the elevator was moving downwards, its velocity is negative. When the button is pushed, it continues to move downwards, but slower. Its velocity is still negative.

The acceleration has the same sign as the velocity if it tends to increase the magnitude of the object, and is negative in the opposite case. Let's look at the formula

\displaystyle a=\frac{v_f-v_o}{t}

In this case, v_f=0 because the elevator will eventually stop, and v_o is negative. It means the acceleration is

\displaystyle a=\frac{-v_o}{t}

It results in a positive value

\boxed{Answer: -,+}

Note: If we chose the opposite references, then the answer would be: +,-

5 0
3 years ago
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