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xeze [42]
2 years ago
7

Classify the following sequences as either arithmetic or geometric. Then state the common difference or ratio and find the missi

ng terms.
_, -9, _, 3, 9....
Mathematics
1 answer:
hjlf2 years ago
8 0
Arithmetic. The common difference is 6 and the blanks are -15 and -3.

Please thank this answer if I helped you!
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Solve for x 3x + 10 - 4 = 21​
Ivan

Answer:

X = 5

Step-by-step explanation:

6 0
3 years ago
Problema de capacidades Una empresa aceitera ha envasado 3000 litros de aceite en 1200 botellas de dos y de cinco litros. ¿Cuánt
mariarad [96]

Answer:

Hay 200 botellas de 5 litros y 1000 botellas de 2 litros.

Step-by-step explanation:

Un sistema de ecuaciones lineales es un conjunto de dos o más ecuaciones de primer grado, en el cual se relacionan dos o más incógnitas.

Resolver un sistema de ecuaciones consiste en encontrar el valor de cada incógnita para que se cumplan todas las ecuaciones del sistema.

En este caso, las variables a calcular son:

  • x= cantidad de botellas de 2 litros.
  • y= cantidad de botellas de 5 litros.

Una empresa aceitera ha envasado 3000 litros de aceite en 1200 botellas de dos y de cinco litros. Entonces es posible plantear el siguiente sistema de ecuaciones:

\left \{ {{2*x+5*y=3000} \atop {x+y=1200}} \right.

Existen varios métodos para resolver un sistema de ecuaciones. Resolviendo por el método de sustitución, que consiste en despejar o aislar una de las incógnitas y sustituir su expresión en la otra ecuación, despejas x de la segunda ecuación:

x= 1200 - y

Sustituyendo la expresión en la primer ecuación:

2*(1200 - y) + 5*y=3000

Resolviendo se obtiene:

2*1200 - 2*y + 5*y= 3000

2400 +3*y= 3000

3*y= 3000 - 2400

3*y= 600

y= 600÷3

y= 200

Reemplazando en la expresión x= 1200 - y:

x= 1200 - y

x=1200 -200

x= 1000

<u><em>Hay 200 botellas de 5 litros y 1000 botellas de 2 litros.</em></u>

7 0
2 years ago
Pls help need help ASAP
aalyn [17]

Answer:

Cameron Boyce is dead like y rip

Step-by-step explanation:

7 0
2 years ago
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Find what the value of x.<br> 60<br> 15<br> 30<br> 45
kondor19780726 [428]

Answer:

ANS;;;; 45 ...........................

6 0
2 years ago
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Define a variable write an equation and solve the problem. the width of a rectangle is 3 meters more than one-fourth its length.
sweet [91]

Let's assume

length of rectangle is L

width of rectangle is W

the width of a rectangle is 3 meters more than one-fourth its length

so,

W=3+\frac{1}{4} L

the perimeter is 10 meters more than twice its length

we know that

perimeter =2(L+W)

so, we get

2(L+W)=10+2L

now, we can simplify it

2L+2W=10+2L

subtract both sides by 2L

2L+2W-2L=10+2L-2L

2W=10

W=5

now, we can find L

5=3+\frac{1}{4} L

subtract both sides 3

5-3=3-3+\frac{1}{4} L

2=\frac{1}{4} L

multiply both sides by 4

4*2=4*\frac{1}{4} L

L=8

so,

length of rectangle is 8 meter

width of rectangle is 5 meter ............Answer

4 0
3 years ago
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