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Deffense [45]
4 years ago
11

Please help meee oh please

Mathematics
1 answer:
irakobra [83]4 years ago
6 0
Collecting the data of this P.G., comes:

The 1st term a_{1} = 648<span>
The 2nd term </span>a_{2} = 216<span>
 
The ratio </span>r = \frac {a2}{a1} &#10;<span>
The number of terms n = 8
 
The 8th term </span>a_{8}  = ?

<span>The value of ratio, we have:
</span>The ratio r = \frac {a2}{a1}
r = \frac {a2}{a1} =  \frac{216}{648}  \frac{\div6}{\div6} = \frac{36}{108} \frac{\div6}{\div6} = \frac{6}{18}  \frac{\div6}{\div6} \to\:r= \frac{1}{3}

<span>Applying the general term formula of P.G., comes:
</span>a_{n} =  a_{1} *r^{n-1}
a_{8} = 648 * (\frac{1}{3}) ^{8-1}
a_{8} = 648 * (\frac{1}{3}) ^{7}
a_{8} = 648 * \frac{1}{3^7}
a_{8} = 648 * \frac{1}{2187}
a_{8} =  \frac{648}{2187}
Simplify

a_{8} = \frac{648}{2187} \frac{\div9}{\div9} = \frac{72}{243} \frac{\div9}{\div9} \to\: \boxed{\boxed{a_{8} = \frac{8}{27}}}\end{array}}\qquad\quad\checkmark

Answer:
\boxed{\boxed{a_{8} = \frac{8}{27}}}



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