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4 years ago

6

Admission to the school fair is $2.50 for students and $3.75 for others. If 2848 admissions were collected for a total of $10,07

8.75, how many students attended the fair?

1 answer:

Novay_Z [31]4 years ago

4 0

Answer:

4031.5

Step-by-step explanation:

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Brianna went on a trip to the art museum and sketched a scale drawing of a rectangular wall mural. She used a scale factor of 0.

GaryK [48]

Answer:

90 inches

Step-by-step explanation:

18 divided by 0.2 is 90

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3 years ago

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Write a recursive formula for the following arithmetic sequence.<br> 8, 5, 2, −1,

Kamila [148]

Answer:

$a_{n}$ = $a_{n-1}$ - 3

Step-by-step explanation:

A recursive formula allows a term in the sequence to be found from the previous term by adding the common difference to it.

Here d = 5 - 8 = - 3, thus

$a_{n}$ = $a_{n-1}$ - 3 with a₁ = 8 ← recursive formula

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4 years ago

A/2(b+c)(d-e)^2 if a=-10, b=10, c=9, d=2, e=5

bearhunter [10]

Answer:

(-86)

Step-by-step explanation:

$\frac{a}{2} (b + c) {(d - e)}^{2} \\ \\ \frac{ - 10}{2} (10 + 9) {(2 - 5)}^{2} \\ - 50 - 45 {( - 3)}^{2} \\ - 50 - 45 (- 3)( - 3) \\ - 50 - 45 + 9 \\ - 95 + 9 = ( - 86)$

8 0

3 years ago

Another question I need help with. I've got the part where it says to rewrite as a radical expression on my paper, but I'm havin

Alik [6]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
32^{\frac{3}{5}}\implies \sqrt[5]{32^3}\qquad 
\begin{cases}
32=2\cdot 2\cdot 2\cdot 2\cdot 2\\
\qquad 2^5
\end{cases}\implies \sqrt[5]{(2^5)^3}\implies \sqrt[5]{(2^3)^5}
\\\\\\
2^3\implies 8$

4 0

4 years ago

Simplify the following leaving your answer in positive index<br><br> 1) (x/y)^-4 x (y/x)^8

Basile [38]

Answer:

$(\frac{x}{y})^{-4} * (\frac{y}{x})^8 = (\frac{y}{x})^{12$

Step-by-step explanation:

Given

$(\frac{x}{y})^{-4} * (\frac{y}{x})^8$

Required

Determine the solution to this

$(\frac{x}{y})^{-4} * (\frac{y}{x})^8$

In law of incides:

$\frac{a}{b} = \frac{b}{a}^{-1}$

This implies that:

$(\frac{x}{y})^{-4} * (\frac{y}{x})^8$ is equivalent to:

$(\frac{y}{x})^{-(-4)} * (\frac{y}{x})^8$

$(\frac{y}{x})^{4} * (\frac{y}{x})^8$

Apply first law of indices:

$(\frac{y}{x})^{4+8$

$(\frac{y}{x})^{12$

Hence:

$(\frac{x}{y})^{-4} * (\frac{y}{x})^8 = (\frac{y}{x})^{12$

5 0

3 years ago