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BigorU [14]
3 years ago
11

Put in Order from least to greatest -10,8,-25,0,-18

Mathematics
2 answers:
Goshia [24]3 years ago
7 0

Answer:

-25,-18,-10,0,8

Step-by-step explanation:

g100num [7]3 years ago
6 0

Answer:

-25,-18,-10,0,8

Step-by-step explanation:

The more negative it is, the more less it is...so if you put them from least to greatest...it is...-25,-18,-10,0,8

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sasho [114]

Answer:

C is correct because if she pays 700 dollars for a car payment her amount of money to spent money ratio will be above the recommended amount of spent money percentage to amount of money ratio, therefore meaning she will be in credit overload.

Step-by-step explanation:

3 0
3 years ago
Add<br> 9a+8b-a+b and 10a-9b+6a-1b
Alina [70]

Answer:

8a + 9b and 16a - 10b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose that g(x) = f(x + 8) + 4. Which statement best compares the graph of g(x) with the graph of f(x)?
UNO [17]
The graph of g(x) is the same as that of f(x), EXCEPT that the graph of f(x) has been translated 8 units to the left and 4 units up.
4 0
3 years ago
Restless Leg Syndrome and Fibromyalgia
Anna11 [10]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.183.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}

            =\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=\frac{0.0066}{0.0066+0.0294}\\\\=0.183333\\\\\approx 0.183

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.183.

3 0
3 years ago
Find the value of the expression
Amiraneli [1.4K]
3m^2+2p^2-15

3(3)^2+2(10)^2-15
3(9)+2(100)-15
21+200-15
206
3 0
3 years ago
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