Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
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The top square is 8. The long rectangle 19.5. The bottom rectangle is 3.
Answer:
Ok so you need the basic which is 334
Step-by-step explanation:
ok 32ftx2= 64 i hope that helps you
Answer:
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Step-by-step explanation:
y = 1.25 ^ x will have the greatest value as x => infinity because the largest exponent in the equation defines that equations end behavior, and y = 1.25^x will have the largest exponent as x => infinity.