Answer:
24a^9 b^11
Step-by-step explanation:
Answer:
Given
f(x) = 2x+7
g(x) = x^2-4
h(x) = 5x
a. 4h(x)
= 4 * 5x
= 20x
b. f(x) - g(x)
f(x) - g(x) = 2x + 7 - (x^2 - 4)
= 2x+7-x^2+4
=-x^2+2x+7+4
=-x^2+2x+11
c. f(g(x)) = 2(g(x))+7
=2(x^2-4) +7
=2x^2-8+7
=2x^2-1
d. g(x)h(x) = (x^2-4)(5x)
= 5x^3 - 20x
e. g(x) / f(x) = x2 - 4/ 2x + 7
Answer:
2 : 3
Step-by-step explanation:
Let,
Radius of cylinder 1 = R
Radius of cylinder 2 = r
Now,
We know that
Volume of cylinder = πr²h
=> πR²h/πr²h' = 20/27
=> R² × 5/r² × 3 = 20/27
=> R²/r² = 20/27 × 3/5
=> R²/r² = 4/9
=> R/r = √(4/9)
=> R/r = 2/3
=> R : r = 2 : 3
Example :
20 + 30.....GCF = 10
10(2 + 3)
The GCF of the number now is 1....because u have basically already factored the GCF out.....leaving only 1 as a factor now
here's another one...
3 + 9...GCF = 3
3(1 + 3)
so the GCF now is 1
