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2 years ago

Help solving this math

Mathematics

1 answer:

VMariaS [17]2 years ago

3 0

Answer:

(1) 9n = 56

n = 6

(2) 10 + 4y = 38

y = 7

(3) 3x + 8x = 55

x = 5

(4) 6m + 20 = 8

m= -2

(5) 17 - 3a = 23

a = -2

(6) 10x + 4 = 6x + 16

x = 3

(7) 4(x - 2) + x = 17

x = 5

(8) 2(x + 3) + 3x = x + 22

x = 4

(9) D. 10

(10) -2(3x - 2.4) = 3(3x - 2.4)

im not sure about this equation

Hope this helps

-Unknown

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When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$