A+B=15 —>A+15=B(plug this into the other equation)
60a+30b=600
60a+30(a+15)=600
60a+30a+150=600
90a+150=600
90a=450
A=5 (plug back in to first equation)
A+B=15
5+B=15
B=10
They have 5 of the Model A and 10 of model B.
We will use integration by substitution, as well as the integrals
∫
1
x
d
x
=
ln
|
x
|
+
C
and
∫
1
d
x
=
x
+
C
∫
x
3
x
2
+
1
d
x
=
∫
x
2
x
2
+
1
x
d
x
=
1
2
∫
(
x
2
+
1
)
−
1
x
2
+
1
2
x
d
x
Let
u
=
x
2
+
1
⇒
d
u
=
2
x
d
x
. Then
1
2
∫
(
x
2
+
1
)
−
1
x
2
+
1
2
x
d
x
=
1
2
∫
u
−
1
u
d
u
=
1
2
∫
(
1
−
1
u
)
d
u
=
1
2
(
u
−
ln
|
u
|
)
+
C
=
x
2
+
1
2
−
ln
(
x
2
+
1
)
2
+
C
=
x
2
2
−
ln
(
x
2
+
1
)
2
+
1
2
+
C
=
x
2
−
ln
(
x
2
+
1
)
2
+
C
Final answer
80-30=50 your answer would be 50
Answer:
There is a $12.00 fee just to enter the park. ... In addition, the tour group charges $0.23 per mile they hike. She brought $35.00 with her. Which equation can be used to determine how many miles can she hike? ... 1. Brainly User. Let, the miles she can travel = d. So, Equation would be: 12.00 + 0.23d = 35.00
Step-by-step explanation:
Points:
Quadrant I: (+, +)
Quadrant II: (-, +)
Quadrant III: (-, -)
Quadrant IV: (+, -)
Thus the point (5,4) is found in Quadrant I.
