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sdas [7]
2 years ago
15

Burger Prince buys top-grade ground beef for $1.00 per pound. A large sign over the entrance guarantees that the meat is fresh d

aily. Any leftover meat is sold to the local high school cafeteria for 80 cents per pound. Four hamburgers can be prepared from each pound of meat. Burgers sell for 60 cents each. Labor, overhead, meat, buns, and condiments cost 50 cents per burger. Demand is normally distributed with a mean of 301 pounds per day and a standard deviation of 37 pounds per day. What daily order quantity is optimal? (Hint: Shortage cost must be in dollars per pound.)
Business
1 answer:
Gnoma [55]2 years ago
7 0

Answer:

The optimal order quantity is 316 pounds

Explanation:

In order to calculate What daily order quantity is optimal, we have to calculate first The cost of underestimating the demand Cu and cost of overestimating demand Co

Cu = ($0.60 - $0.50)*4 = $0.40

Co = $1 - $0.80 = $0.20

Next we have to calculate the Service Level = Cu / (Cu + Co)

= 0.40 / (0.40 + 0.20)

= 0.40/0.60

= 0.6667

So, Z Value at above service level = 0.430727

Therefore, in order to calculate the Optimal Order quantity, we would have to use the following formula

Optimal Order quantity= Mean + Z Value × Std Deviation

= 301 + 37 * 0.430727

= 301 + 15.36899

= 316 pounds

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Explanation:

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3 years ago
Which is the best answer
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The answer would be between A and D.
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Radovilsky Manufacturing Company, in Hayward, California, makes flashing lights for toys. The company operates its production fa
Anna007 [38]

Answer:

Given,

Annual demand, D = 12500,

Setting up cost, S = $ 49,

Production rate per year, P =  production facility × capability of production = 300 × 105 = 31500,

Holding cost per year, H = $ 0.15,

Hence,

(i) Optimal size of the production run,

Q = \sqrt{\frac{2DS}{H(1-\frac{D}{P})}}=\sqrt{\frac{2\times 12500\times 49}{0.15(1-\frac{12500}{31500})}}=3679.60238126\approx 3680

(ii) Average holding cost per year,

=\frac{QH}{2}(1-\frac{D}{P})

=\frac{3680\times 0.15}{2}(1-\frac{12500}{31500})

=166.476190476

\approx \$ 166.48

(iii) Average setup cost per year,

=\frac{D}{Q}\times S

=\frac{12500}{3680}\times 49

=166.44021739

\approx \$ 166.44

(iv) Total cost per year = average setup cost per year + average holding cost per year + cost to purchase 12500 lights

= 166.44 + 166.48 + 12500(0.95)

= $ 12207.92

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2 years ago
Finding the required interest rate: Your parents will retire in 18 years. They currently have $250,000, and they think they will
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Answer:

i= 8% annual compunded

Explanation:

Giving the following information:

Your parents will retire in 18 years. They currently have $250,000, and they think they will need $1,000,000 at retirement.

We need to calculate the interest rate required to reach the $1 million goal in 18 years without any additional deposit.

FV= PV*(1+i)^n

Isolating i:

i= [(FV/PV)^(1/n)] - 1

i= [(1,00,000/250,000)^(1/18)] - 1= 0.08

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