Answer:
Step-by-step explanation:
We know that , the equation of a line that passes through (a,b) and (c,d) is given by :_

Standard form of equation of line = 
Given points = (7, -3) and (4, -8)
Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -

[∵ (-)(-)=(+)]
Or
Hence, the required equation :-
2
+
4
5
=
−
1
4
x
2
+
45
=
−
14
x
x2+45=−14x
2
+
4
5
−
−
1
4
=
0
The straight lines are asking to find the modulus or the size of the complex number.
For a complex number z = x + iy, [z] = √(x^2 +y^2)
Where x = Real Number, y = Imaginary number.
For 3 +i, x = 3, y = 1 (Note y is what number that is attached to i)
[3 + i] = √(3^2 +1^2) = √10 = 3.162
Answer:
The length of all four sides of a quadrilateral are 7 inches, 14 inches, 10 inches, 10 inches
Step-by-step explanation:
Let the shortest side be 
As per given information longest side = 
and other 2 sides are equal in length but 3 more times that shortest side = 
Perimeter of Quadrilateral = 41 inches given
But perimeter of quadrilateral = sum of all sides

Shortest side = 
Longest side = 
Other 2 sides = 
I: y=(1/2)x+5
II: y=(-3/2)x-7
substitution:
fancy word for insert the definition of one variable in one equation into the other
-> isolate a variable, luckily y is isolated (even in both equations) already
-> substitute y of II into I (=copy right side of II and replace y in I with it):
(-3/2)x-7=(1/2)x+5
-3x-14=x+10
-3x-24=x
-24=4x
-6=x
-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2
elimination: subtract one equation from the other to eliminate a variable, again y is already isolated->no extra work required
I-II:
y-y=(1/2)x+5-[(-3/2)x-7]
0=(1/2)x+5+(3/2)x+7
0=(4/2)x+12
-12=2x
-6=x
-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2