To effectively determine the correct answer, it would be helpful to write this into an algebraic expression. We let x as the number. We do as follows:
<span>Four times the square of a certain number increased by 6 times the number equals 108.
4x^2 + 6x = 108
The numbers can be either of the following since the equation generated was a quadratic equation which has two roots.
x = 4.5
x = -6 </span>
Answer:
The graph is symmetric about the origin.
The graph does not pass through the origin.
Step-by-step explanation:
We're given:
- the function y=axn
- a = 1
- n is odd
Because a = 1, then the given function can be rewritten as y = n.
The function y = n will produce a horizontal line. Any function in the form of y = a single number, such as 4 or 9.3 will produce a horizontal line.
- The graph is symmetric about the origin.
This is true, given the graph is a horizontal line.
- The graph does not pass through the origin.
This is also true. We're given that n is an odd number. The graph will only pass through the origin if n = 0, and 0 is even.
- The graph has more than one x-intercept.
This would only be true when n = 0, and this isn't possible. So, no.
I can solve with 2 methods:
I. Because the discount is 15 % of 18 $ , the price will be (100-15=85) 85 % of 18 $
18*85/100= 15,3 $ ( the sale price)
II. The discount is 15 % of 18$
15*18/100= 2,7$ ( the discount)
then I decrease it from the regularly price
18$-2,7$=15,3 $ (the sale price)
Personally I believe the first is an easier method.
I hope you understand and you can apply this in every similary problem.
Answer is x7 becuse i found it
Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
