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jek_recluse [69]
3 years ago
7

I need help ASAP.

Mathematics
1 answer:
Bingel [31]3 years ago
8 0

9/15

8.3%

Step-by-step explanation:

the total amount of trials was fifteen and head was scored 9 times so 9/15

the odds of a dice roll is 1/6 or 16.66% and a coin is 50%. To get both to happen in an ideal circumstance we multiply the odds so we multiply 1/6 and 1/2

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           \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

       <em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em>         </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

       Replace c with 6, and d with 7:-

     \Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}

\bigstar On simplification,

   \Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}

\bigstar On further simplification,

    \Large\text{$\displaystyle\frac{6}{4} +21$}

\bigstar On further simplification,

     \Large\text{$\displaystyle\frac{6}{4}+\frac{84}{4}$}

\bigstar Adding the numerators,

\Large\text{$\displaystyle\frac{90}{4}$}

\bigstar Finally, Reducing the fraction:-

\Large\text{$\displaystyle\frac{45}{2}$}

\Uparrow \mathbb{OUR\:SIMPLIFIED\:EXPRESSION}

<h3>Good luck with your studies.</h3>

         \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}

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