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4 years ago

Is the equation 3+z=-19 true false or open

Mathematics

2 answers:

Ksenya-84 [330]4 years ago

4 0

Subtract 3 from both sides to get

3+z=-19

3+z-3=-19-3

z = -22

So it's true when z = -22.

kirill [66]4 years ago

3 0

It would be an open answer

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Use Euler’s method to estimate the value of y(20). Use a step size of ∆x = 5. Please fill out the remainder of the chart complet

crimeas [40]

Answer:

y(20)=14,322

Step-by-step explanation:

We need to solve the equation:

$dy/dx=0.4xy$

with initial point

$y(0) = 2$

with incerments

$\Delta x=h=5$

By Euler's method, we have:

$y(x+h)=y(x)+h*f'(x,y)$

We start with the initial point

$y(5)=y(0)+5*f'(0,2)=2+5*(0.4*0*2)=2$

And we continue until we reach the value for y(20)

$y(10)=y(5)+5*f'(5,2)=2+5*(0.4*5*2)=2+20=22\\\\\\y(15)=y(10)+5*f'(10,22)=22+5*(0.4*10*22)=22+440=462\\\\\\y(20)=y(15)+5*f'(15,462)=462+5*(0.4*15*462)=462+13,860\\\\y(20)=14,322$

4 0

3 years ago

Find two consecutive even integers such that the square of the second, decreased by twice the first is 52

Fiesta28 [93]

Let the first integer be $x$ . So, the next even number is $x+2$

Let's translate the formula: the square of the second is $(x+2)^2$ , twice the first is $2x$ . So, the equation is

$(x+2)^2 - 2x = 52$

Expand the square to get

$x^2+4x+4-2x = 52 \iff x^2+2x+4 = 52 \iff x^2+2x - 48 = 0$

The solutions to this equations are

$x = -8,\quad x = 6$

So, the possible consecutive even numbers are

$-8\text{ and } -6\quad\text{or}\quad 6\text{ and } 8$

8 0

3 years ago

What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?

Akimi4 [234]

Answer:

25.6 units

Step-by-step explanation: From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

Read more on Brainly.com - brainly.com/question/12560433#readmore

8 0

3 years ago

15(d + 7) = 4(d - 4) + 11d has how many solutions?

svp [43]

$15(d + 7) = 4(d - 4) + 11d\\\\15d+105=4d-16+11d\\\\15d-4d-11d=-16-105\\\\0=-121$

no solution

4 0

4 years ago

Use the tables to create the function in slope intercept form

Ivan

1. y = 4x + 9 ; m = 4 ; b = 9

the slope is 4 because there’s a pattern of +4 going down the function table in the “y” column

and b= 9 because at the number 0 on the x line has 9 in the y box

2. y = 3x - 1 ; m = 3 ; b = -1

basically the same thing as the first one just different numbers

6 0

3 years ago