All categories

3 years ago

You too personal reasoning to find 65% of 200

Mathematics

2 answers:

harina [27]3 years ago

7 0

We have an equation: ?/200 = 65/100

Cross multiply:
100*?= 65*200
⇒ ?= 65*200/100= 130

65% of 200 is 130~

rewona [7]3 years ago

6 0

Multiply 0.65 by 200. The answer is 130.

You might be interested in

A jar of jelly that weighs 4.25 ounces costs $2.89. What is the cost of one ounce of jelly?

maria [59]

4.25 + $2.89.= $7. 1 4

4 0

4 years ago

Abdul was scuba diving 76 feet below the surface of the ocean. To get a closer look at a school of fish, he swam up 28 feet

harkovskaia [24]

Answer:

He is at 48 feet below the surface

Step-by-step explanation:

76-28= 48

5 0

3 years ago

Read 2 more answers

Suppose you need to deliver 40 terabytes of data to your co-workers in Atlanta (200 km). You have an available 100 Mbps dedicate

Marat540 [252]

Answer: All data will be sent in 89.39 hours

Step-by-step explanation:

Data transfer rate: 100 Mbps=100 $\frac{Mb}{s}$ × $\frac{1Tb}{1024^{2} Mb}$ × $\frac{3600s}{h}$ =0.3433 $\frac{Tb}{h}$

The pigeon can fly 1000 km/day and it needs to fly 400 km (round trip).

Pigeon rate: $\frac{1000km}{24h}$ =41.67 $\frac{km}{h}$

Time of round trip: 400 km÷ $\frac{1000km}{24h}$ =9.6 h

So the pigeon can send 1 Tb every 9.6 hours.

If we sum the rates we can get the time for sending all the data:

40 Tb= (0.3433 Tb/h + 1 Tb/9.6h)×t

T= 89.39 hours

8 0

4 years ago

Find the value of x.

Otrada [13]

Answer:

the value of x is 29°

hope it helps

have a nice day

5 0

3 years ago

The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?

MaRussiya [10]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}$

$~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill$

3 0

1 year ago