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Irina-Kira [14]
4 years ago
8

Simplify and solve this equation for q: 3q + 5 + 2q – 5 = 65.

Mathematics
1 answer:
gladu [14]4 years ago
3 0

3q+5+2q-5 = 65

5q = 65

q = 13

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Juan joins a movie club. He pays $10 to join and each movie cost $5. Which equation represents the relationship between the y ,
TiliK225 [7]
Y = 5x + 10. X represents the number of movies, and Y is the cost per month.
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3 years ago
Eight times the reciprocal<br> of a number equals 4 times<br> the reciprocal of 10.
saveliy_v [14]

Answer:

8(1/x) = 4(1/10)

Step-by-step explanation:

lets say the number is x

eight times the reciprocal of a number equals 4 times the reciprocal of 10

  8       *                       1//x                            =        4    *         1/10

8/x = 4/10 ,  cross multiply

4x =8*10, divide both sides by 4

x= 80/4

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8 0
3 years ago
W+8=-3<br> i don't understand how to solve the problem
Bogdan [553]

Answer:

It is negetive 11

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
The breaking strength of a rivet has a mean value of 10,000 psi and a standard deviation of 500 psi. (a) What is the probability
velikii [3]

Answer:

a) 89.05% probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200

b) No, because one of the requirements of the central limit theorem is a sample size of at least 30.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 10000, \sigma = 500

(a) What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200?

Here we have n = 40, s = \frac{500}{\sqrt{40}} = 79.06

This probability is the pvalue of Z when X = 10200 subtracted by the pvalue of Z when X = 9900. So

X = 10200

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{10200 - 10000}{79.06}

Z = 2.53

Z = 2.53 has a pvalue of  0.9943.

X = 9900

Z = \frac{X - \mu}{s}

Z = \frac{9900 - 10000}{79.06}

Z = -1.26

Z = -1.26 has a pvalue of  0.1038.

0.9943 - 0.1038 = 0.8905

89.05% probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200

(b) If the sample size had been 15 rather than 40, could the probability requested in part (a) be calculated from the given information?

No, because one of the requirements of the central limit theorem is a sample size of at least 30.

3 0
3 years ago
The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act
cluponka [151]

Answer: 0.3061.

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean \mu, the actual temperature of the medium, and standard deviation \sigma.

Let X be the random variable that represents the reading of the thermometer.

Confidence level : =95\%

We know that the z-value for 95% confidence interval is 1.96.

Then, we have

-1.96      z=\dfrac{X-\mu}{\sigma}

\Rightarrow\ -1.96\sigma  

But all readings are within 0.6° of \mu.

So, 1.96\sigma=0.6  

\Rightarrow\ \sigma=\dfrac{0.6}{1.96}=0.30612244898\approx0.3061

Hence, the required standard deviation will be  

7 0
3 years ago
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