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Galina-37 [17]
3 years ago
5

What is 5 and 4/5 plus 1 and 1/8? Please help. Thx

Mathematics
1 answer:
faltersainse [42]3 years ago
7 0
First make the mixed numbers into improper fractions and then find the LCD then combine which will give you the answer of 277 / 40
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Estimates show that there are 1.4*10^8 pet fish and 9.4*10^6 pet reptiles in the United States.
Readme [11.4K]
\bf \stackrel{fish}{1.4\times 10^8}~~+~~\stackrel{reptiles}{9.4\times 10^6}
\\\\\\
\stackrel{fish}{140000000}~~+~~\stackrel{reptiles}{9400000}\implies 
\begin{array}{rrrrllll}
140000000\\
+9400000\\
\text{\textemdash\textemdash\textemdash\textemdash\textemdash}\\
149400000
\end{array}\implies 1.494\times 10^8
5 0
3 years ago
Use the FOIL method to find the product below. (x + 3)(x2 – 6x)
Phoenix [80]
(x + 3) • (2x - 6x)
collect like terms
(x + 3) • (-4x)
distribute -4x through the parentheses

Answer: -4x^2 - 12x

Hope this helps!
6 0
4 years ago
Which equation shows exponential GROWTH?<br> A) y=.5^x<br> B) y=.25^x<br> C) y= 25^x<br> D) y= .2^x
eduard

c) y = 25^x

explanation

because y increase as x increases

7 0
3 years ago
How can I find equivalent expressions to the given expression?
nlexa [21]

Answer:

\frac{36t^2}{6^t} ~~ Not ~Equivalent

\frac{6t^2}{36^t} ~ ~Equivalent   ✔︎

6^{t^2} *36^t ~~ Not~ Equivalent

᪥༄᪥༄᪥༄᪥༄᪥༄᪥༄

Hope it helps...

Have a great day!!.

8 0
3 years ago
Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4). What is the y-coordinate of the midpoint of line segment YZ?
tatiyna

Given:

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).

To find:

The y-coordinate of the midpoint of line segment YZ.

Solution:

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:

Midpoint=\left(\dfrac{-3+7}{2},\dfrac{-6+4}{2}\right)

Midpoint=\left(\dfrac{4}{2},\dfrac{-2}{2}\right)

Midpoint=\left(2,-1\right)

Therefore, the y-coordinate of the midpoint of line segment YZ is -1.

8 0
3 years ago
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