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BigorU [14]
3 years ago
14

The scatter plot shows the time spent studying, x, and the midterm score, y, for each of 24 students.

Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:

nope I don't think so..

u can't become a nationalist without becoming a facists

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Pls answer and get branily
Dennis_Churaev [7]

Answer:

Just put 4 basketballs and 5 baseballs in each one

Step-by-step explanation:

If you think about it you will know that each ratio there is the same. So, you do the same thing each time.

All you have to do now is read. It says put 4 basketballs and 5 baseballs.

I hope this helped ;)

6 0
3 years ago
The average score on a standardized test is 750 points with a standard deviation of 50 points. What is the probability that a st
nalin [4]
The probability that student scored more than 850 we shall proceed as follows:
z=(x-μ)/σ
where:
x=850
μ=750
σ=50
thus
z=(850-750)/50
z=2
thus
P(x>850)=1-P(x<850)=1-P(z<2)=1-0.9772=0.0228

Answer: P(x>850)=0.0228
4 0
3 years ago
Read 2 more answers
The line that goes horizantally (left to right) across the graph is called what? *
kodGreya [7K]

Step-by-step explanation:

horizontal line I believe

5 0
3 years ago
Someone help please
Alla [95]

Answer:  Choice A

\tan(\alpha)*\cot^2(\alpha)\\\\

============================================================

Explanation:

Recall that \tan(x) = \frac{\sin(x)}{\cos(x)} and \cot(x) = \frac{\cos(x)}{\sin(x)}. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why \tan(\alpha)*\cot^2(\alpha)\\\\ is identical to \frac{\cos(\alpha)}{\sin(\alpha)}\\\\

Therefore, \tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that \tan(\alpha)*\cot^2(\alpha)\\\\ is the same as \frac{\cos(\alpha)}{\sin(\alpha)}\\\\ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0
2 years ago
Find the value of X.
shtirl [24]

Answer:

x=15º

Step-by-step explanation:

180=25+8x+5+2x

180=30+10x

180-30=10x

150=10x

15=x

4 0
2 years ago
Read 2 more answers
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