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Olin [163]
3 years ago
15

I need to know how to simplify this equation

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

\frac{ {3}^{x + 4} -  {3}^{2x + 2}  }{ {3}^{x - 2} \times  {3}^{x + 4}  }  =   \frac{x + 4 - 2x - 2}{(x - 2) \times (x + 4)}  =  \frac{ - x + 2}{ {x}^{2} + 4x - 2x - 8 }  =  \frac{ - x + 2}{ {x}^{2}  + 2x - 8}
i could be wrong, was kinda in a rush
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What is the LCM of 13/16a^3b^3, 11/30a^5b
vichka [17]

Answer:

The L.C.M of given numbers is \frac{143}{240}a^5b^3.

Step-by-step explanation:

The given expressions are

\frac{13}{16}a^3b^3

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The factors of given expressions are

\frac{13}{16}a^3b^3=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b

\frac{11}{30}a^5b=\frac{11}{15}\times \frac{1}{2}\times a\times a\times a\times a\times a\times b

L.C.M.=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b\times \frac{11}{15}\times a\times a

L.C.M.=\frac{143}{240}\times a^5\times b^3

L.C.M.=\frac{143}{240}a^5b^3

Therefore, the L.C.M of given numbers is \frac{143}{240}a^5b^3.


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